-190-9x+x^2=0

Solution for -190-9x+x^2=0 equation:

-190-9x+x^2=0

a = 1; b = -9; c = -190;
Δ = b2-4ac
Δ = -92-4·1·(-190)
Δ = 841
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{841}=29$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-9)-29}{2*1}=\frac{-20}{2}
=-10
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-9)+29}{2*1}=\frac{38}{2}
=19
$